12b^2+102b+28=-2b^2

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Solution for 12b^2+102b+28=-2b^2 equation:


Simplifying
12b2 + 102b + 28 = -2b2

Reorder the terms:
28 + 102b + 12b2 = -2b2

Solving
28 + 102b + 12b2 = -2b2

Solving for variable 'b'.

Combine like terms: 12b2 + 2b2 = 14b2
28 + 102b + 14b2 = -2b2 + 2b2

Combine like terms: -2b2 + 2b2 = 0
28 + 102b + 14b2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(14 + 51b + 7b2) = 0

Factor a trinomial.
2((7 + b)(2 + 7b)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(7 + b)' equal to zero and attempt to solve: Simplifying 7 + b = 0 Solving 7 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + b = 0 + -7 b = 0 + -7 Combine like terms: 0 + -7 = -7 b = -7 Simplifying b = -7

Subproblem 2

Set the factor '(2 + 7b)' equal to zero and attempt to solve: Simplifying 2 + 7b = 0 Solving 2 + 7b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 7b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 7b = 0 + -2 7b = 0 + -2 Combine like terms: 0 + -2 = -2 7b = -2 Divide each side by '7'. b = -0.2857142857 Simplifying b = -0.2857142857

Solution

b = {-7, -0.2857142857}

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